The standard molar heat of vaporization for water is 40.79 kJ/mol. How much energy
would be required to vaporize 2.00 mol of
water?
Answer in units of kJ.
To find the amount of energy required to vaporize 2.00 mol of water, we can use the given standard molar heat of vaporization.
The standard molar heat of vaporization is the amount of energy required to vaporize one mole of a substance at its boiling point. In this case, the standard molar heat of vaporization for water is 40.79 kJ/mol.
To find the amount of energy required to vaporize 2.00 mol of water, we can multiply the number of moles by the standard molar heat of vaporization:
2.00 mol * 40.79 kJ/mol = 81.58 kJ
Therefore, it would require 81.58 kJ of energy to vaporize 2.00 mol of water.