What is the molarity of 83.0 grams of KI dissolved in 500.0 ml of water
the answer is 1.0M
is the answer 2
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). Here's how you can calculate the molarity of the KI solution:
Step 1: Calculate the number of moles of KI:
To find the number of moles, you need to divide the mass of KI by its molar mass. The molar mass of KI is calculated by adding up the atomic masses of potassium (K) and iodine (I). The atomic mass of potassium is 39.1 grams per mole, and the atomic mass of iodine is 126.9 grams per mole.
Molar mass of KI = (39.1 g/mol) + (126.9 g/mol) = 166.0 g/mol
Number of moles of KI = Mass of KI / Molar mass of KI
= 83.0 g / 166.0 g/mol
= 0.500 mol
Step 2: Convert the volume of the solution to liters:
The volume given in the problem is 500.0 mL. Since the molarity of a solution is measured in liters, you need to convert milliliters to liters by dividing by 1000:
Volume of solution = 500.0 mL / 1000 mL/L
= 0.500 L
Step 3: Calculate the molarity of the solution:
Now that you have the number of moles of KI (0.500 mol) and the volume of the solution (0.500 L), you can use the formula for molarity:
Molarity (M) = Number of moles of solute / Volume of solution in liters
= 0.500 mol / 0.500 L
= 1.00 M
Therefore, the molarity of the KI solution is 1.00 M.
molarity is moles/liter
so, how many moles in 83 grams?
how many liters in 500ml?