The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each side, if the triangle has a perimeter of 28 inches?
Third Side>First Side>Second Side
x-2>x>x+3
x+x+x+3+-2=3x+1
28-1=27
27/3=9
x=9
x+3=12
x-2=7
Answer: Third Side=7 First Side=9 Second Side=12
woops it's meant to be x-2<x<x+3
The second side of a triangle is 7 inches more than the first side. The third side is 4 inches less than 3 times the first. The perimeter is 28 inches.
idk bro
To solve this problem, we can set up a system of equations based on the given information. Let's call the first side "x" inches long.
According to the given information, the second side is 3 inches longer than the first side. This means the second side is (x + 3) inches long.
Similarly, the third side is 2 inches shorter than the first side. So, the third side is (x - 2) inches long.
The perimeter of a triangle is the sum of all three sides. According to the problem, the perimeter is 28 inches. Therefore, we can write the equation:
x + (x + 3) + (x - 2) = 28
Now, let's solve this equation to find the value of x:
3x + 1 = 28
3x = 28 - 1
3x = 27
x = 27 / 3
x = 9
So, the first side of the triangle is 9 inches long.
Using this information, we can calculate the lengths of the other two sides:
Second side = x + 3 = 9 + 3 = 12 inches
Third side = x - 2 = 9 - 2 = 7 inches
Therefore, the lengths of the sides of the triangle are: 9 inches, 12 inches, and 7 inches.
Sketch it out :)
One side is 3 shorter then the other, so you need x + 3 to reach the x side. The other side is x - 2, and the other side is x.
P = s + s + s
28 = x + x - 2 + x + 3
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solve...