Balance and classify (show work )
LiOH + Fe (NO3)3 ->>>
3LiOH + Fe (NO3)3 ->>> 3LiNO3 + Fe(OH)3
This can be classified as a double displacement or as a precipitation reaction
To balance the given chemical equation and classify the reaction, we need to follow a step-by-step process:
Step 1: Write down the unbalanced chemical equation:
LiOH + Fe(NO3)3 →
Step 2: Count the number of atoms for each element on both sides of the equation.
On the left-hand side (LHS):
Li: 1 atom
O: 1 atom
H: 1 atom
On the right-hand side (RHS):
Fe: 1 atom
N: 3 atoms
O: 9 atoms
Step 3: Balance the equation by adjusting the coefficients in front of the chemical formulas. Start by looking at the elements that occur in the fewest compounds.
Let's start with the lithium (Li) atom, which is only present on the LHS. Therefore, we need a coefficient of 1 in front of LiOH:
LiOH + Fe(NO3)3 →
Next, let's balance the oxygen (O) atoms. There are three oxygen atoms on the RHS due to the presence of NO3 in Fe(NO3)3. We can balance this by placing a coefficient of 3 in front of LiOH:
3LiOH + Fe(NO3)3 →
Now, let's count the hydrogen (H) atoms. There are three hydrogen atoms on the LHS, and they are already balanced.
3LiOH + Fe(NO3)3 →
Next, let's balance the nitrogen (N) atoms. There is just one nitrogen atom on the RHS. To balance this, place a coefficient of 3 in front of Fe(NO3)3:
3LiOH + 3Fe(NO3)3 →
Finally, the iron (Fe) atoms are balanced since there is one on both sides.
The balanced equation is:
3LiOH + 3Fe(NO3)3 → 3LiNO3 + Fe(OH)3
Step 4: Classify the reaction. In this case, the reaction is a double displacement or metathesis reaction as the cations (Li+ and Fe3+) and anions (OH- and NO3-) swap places to form new compounds.
To summarize:
Balanced equation: 3LiOH + 3Fe(NO3)3 → 3LiNO3 + Fe(OH)3
Classification: Double displacement or metathesis reaction