How far will a move in 4 seconds if uniformly accelerated from rest at the rate of 2ms-2?(ssce June 1993)

You dropped some information...Mass?

V = Vo + a*t = 0 + 2*4 = 8 m/s. = Final velocity.

V^2 = Vo^2 + 2a*d = 8^2.
0 + 4*d = 64,
d = 16 m.

To find out how far an object will move in 4 seconds when uniformly accelerated from rest at a given rate, we can use the equation of motion:

\(s = ut + \frac{1}{2}at^2\)

Where:
- \(s\) is the distance covered
- \(u\) is the initial velocity (which is 0 in this case, as it starts from rest)
- \(a\) is the acceleration (2 m/s\(^2\) in this case)
- \(t\) is the time duration (4 seconds in this case)

Substituting the known values into the equation, we get:

\(s = 0 \cdot 4 + \frac{1}{2} \cdot 2 \cdot (4)^2\)

Simplifying further:

\(s = 0 + \frac{1}{2} \cdot 2 \cdot 16\)

\(s = 0 + 16\)

Therefore, the object will move a distance of 16 meters in 4 seconds when uniformly accelerated from rest at the rate of 2 m/s\(^2\).