A 25g ball slides down a smooth inclined plane. 0.850m high, that makes an angle of 35 degrees with the horizontal. The ball slides into an open box of 200g mass and they slide off the end of the table 1m high. How far from the base of the table will the combined ball and box hit the ground.

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  1. KE = PE.
    0.5*M*V^2 = M*g*h,
    Divide both sides by 0.5M:
    V^2 = 2g*h = 19.6 * 0.85 = 16.66,
    V = 4.1 m/s. @ bottom of incline.

    h = 0.5g*t^2 = 1 m.
    4.9t^2 = 1,
    t = 0.45 s.
    d = Vx * t = 4.1 * 0.45 =

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