algebra

So here's the problem:

6a^-2 + 9a^2 all over 3a^-2

The answer is suppose to be 2 + 3a^4

I keep getting the answer as 5.

Can you show me how to solve this problem correctly?

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  1. how about multiplying top and bottom of your fraction by a^2 to get

    (6 + 9a^4)/3
    = 2 + 3a^4

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