A man pulls a drum of oil 10kg upon an inclined plane OA.if OA=5m and AB=3m as shown below in a triangle. Calculate the A the potential energy at A and workdone by the man.
If AB is vertical, then change Potential energy=mgh=10*9.8*3 joules
The man supplied that work.
At the back of my txt bk the ans is 300j in each case
300j
To find the potential energy at point A, we need to use the formula:
Potential Energy = mass * gravitational acceleration * height
In this case, the mass of the drum of oil is given as 10kg, and the gravitational acceleration is approximately 9.8 m/s^2.
To find the height, we need to calculate the vertical distance from point B to point A, as the inclined plane is tilted.
Using the Pythagorean theorem, we can find the height as follows:
Height^2 = (Length of AB)^2 - (Length of OA)^2
Height^2 = 3^2 - 5^2
Height^2 = 9 - 25
Height^2 = -16
Since we cannot take the square root of a negative number, it means that there is no real height between points A and B. Therefore, the potential energy at point A is zero.
Now let's move on to calculating the work done by the man.
Work Done = Force Applied * Distance
Force Applied = Mass * Gravitational Acceleration
The force applied will be equal to the weight of the drum of oil, which we can find using the formula:
Weight = Mass * Gravitational Acceleration
Weight = 10kg * 9.8 m/s^2
Weight = 98 N
Now, the distance over which the man pulls the drum is the length of OA, which is given as 5 meters.
Work Done = Force Applied * Distance
Work Done = 98 N * 5 m
Work Done = 490 Nm (or Joules)
Therefore, the work done by the man is 490 Joules.