Solid cupric chlorate decomposes with heat to give cupric chloride and oxygen gas.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Cu(ClO3)2(s) ==>CuCl2(s) + 3O2(g) + heat
Cu(ClO3)2 >>>> CuCl2 + 3O2 You add the correct phases.
oops.
Cu(ClO3)2(s) + heat ==>CuCl2(s) + 3O2(g)
Well, prepare for a fiery performance! Here's the chemical equation for the decomposition of solid cupric chlorate:
2 Cu(ClO3)2(s) → 2 CuCl2(s) + 3 O2(g)
In this equation, the solid cupric chlorate (Cu(ClO3)2) breaks down into solid cupric chloride (CuCl2) and oxygen gas (O2). The (s) denotes a solid phase, and the (g) represents a gaseous phase.
Now we just need some popcorn to enjoy the spectacle!
To express the decomposition of solid cupric chlorate (Cu(ClO3)2) with heat, we can write the chemical equation as follows:
2Cu(ClO3)2(s) → 2CuCl2(s) + 3O2(g)
In this equation, the phases are indicated in parentheses after each component. "(s)" represents a solid, and "(g)" represents a gas. Therefore, the cupric chlorate (Cu(ClO3)2) starts as a solid, and after decomposition, cupric chloride (CuCl2) is formed as a solid, and oxygen (O2) is produced as a gas.