Physics: Newton's third law

A passenger in a boat approaching a dock attempts to step onto the dock before the boat has been tied up. The passenger, whose mass is 57 kg, accelerated at a rate of 3.2 m/s^2 [forward]. If the mass of the boat is 97 kg, what is the boat's acceleration relative to the passenger? Neglect the horizontal force of the water.

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  1. Sorry, I forgot to add the second part of the question.

    What is the net acceleration of the passenger relative to the dock?

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  2. 1.9m/s2 backwards

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  3. 57kg x 3.2m/s2 forward = 182.4

    182.4/97kg = 1.88 round to two significant figures so
    1.9m/s2 backwards

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