math/pre-calc

"The roadrunner is standing under the edge of a cliff 570 feet above the ground. Wile E Coyote is 10 feet above the ground on a ledge below the roadrunner. Wile E. has purchased a spring catapult from ACME. The catapult will propel Wile E. with an upward velocity of 100 feet per second. The equation that gives the height, h, of Wile E. Coyote above the ground t seconds after he releases the catapult is given: h(t)=-4.9t^2+100t+10" When does the coyote reach the maximum height? I really cannot figure this one out. Thank You!

1. 👍 0
2. 👎 0
3. 👁 81
1. tmax lies on the axis of symmetry of the parabola ... -b / 2a ... -100 / (2 * -4.9)

1. 👍 0
2. 👎 0
posted by R_scott
2. First of all, your equation starting with -4.9t^2 + .... would be valid for metres and not for feet, on top of that the +100t would be the correct term for units in feet.
All other units are in feet, what a messed-up question.
So check on the wording of the question ....

I will assume that all measurements are in metres.

The max height will be obtained at the vertex of
h = -4.9t^2 + 100t + 10
the t of the vertex = -b/(2a) = -100/-9.8 = 10.204..
So the max height above ground is obtained after 10.2 seconds

at that t, h = -4.9(10.204.)^2 + 100(10.204..) + 10 = 520.204 m

Since the cliff is 570 m high, as usual the coyote will fail and probably crash
and in typical cartoon fashion, not hurt himself.

1. 👍 0
2. 👎 0
posted by Reiny

Similar Questions

1. PHYSICS

Wile E. Coyote is holding a “HEAVY DUTY ACME ANVIL” on a cliff that is 40.0 meters high. The Roadrunner (beep-beep), who is 1.0 meter tall, is running on a road toward the cliff at a constant velocity of 10.0 m/s. Wile E.

asked by Jin on November 9, 2009
2. physics

The determined Wile E. Coyote is out once more to try to capture the elusive roadrunner. The coyote wears a new pair of Acme powered roller-skates, which provide a constant horizontal acceleration of 13 m/s2. The coyote starts off

asked by julymoe on September 22, 2010
3. Wile E. Coyote

The determined Wile E. Coyote is out once more to try to capture the elusive roadrunner. The coyote wears a new pair of power roller skates, which provide a constant horizontal acceleration of 15 m/s2, as shown in the figure

asked by D ~ Day on September 12, 2012
4. Physics

The determined Wile E. Coyote is out once more to try to capture the elusive roadrunner. The coyote wears a new pair of Acme power roller skates, which provide constant horizontal acceleration of 15 m/s^2. The coyote starts off at

asked by Mary on September 21, 2009
5. Math

A ball is kicked off the top of a cliff that is 30 feet tall at an angle of 45° to the horizontal with an initial velocity of 25 feet per second. The quadratic equation shown below models the height, h(x), of the ball when it is

asked by Gyro Zeppeli on April 9, 2019
6. Math

For this problem, a person standing on the edge of a cliff throws a rock directly upward. it is observed that 2 secs later the rock is at its maximum height (in feet) and that 5 secs after that (meaning 7 seconds after being

asked by Leah on October 7, 2014
7. physics

Wile E Coyote, having missed the Road Runner, leaves the edge of the cliff at 29 m/s horizontal velocity. If the canyon is 104 m deep, how far from the base of the cliff does the coyote land?

asked by Cali on June 1, 2018
8. Physics

A diver in Acapulco jumps off a 150 ft cliff. His forward motion is 10 feet per second. The base of the cliff at the waters edge extends 38 feet beyound the top edge of the cliff. Will the diver land in the water?

asked by Clay on October 26, 2011
9. Physics

A diver in Acapulco jumps off a 150 ft cliff. His forward motion is 10 feet per second. The base of the cliff at the waters edge extends 38 feet beyound the top edge of the cliff. Will the diver land in the water?

asked by Clay on October 25, 2011
10. Physics

A person standing at the edge of a seaside cliff kicks a stone horizontally over the edge with a speed of 14.3 m/s. The cliff is 47.6 m above the water's surface. How far in meters from the base of the cliff does the stone land?

asked by Asia on November 13, 2012

More Similar Questions