What is the molar ratio of oxygen to magnesium oxide in the chemical equation? Show work
2Mg + O2 ->2MgO
1mole O2 : 2 mole MgO That's all the work needed.
In the chemical equation, 2Mg + O2 -> 2MgO, the reaction shows that 2 moles of magnesium (Mg) combines with 1 mole of oxygen (O2) to form 2 moles of magnesium oxide (MgO).
To determine the molar ratio, we compare the coefficients of the reactant (oxygen) and the product (magnesium oxide).
The coefficient of the reactant oxygen (O2) is 1, and the coefficient of the product magnesium oxide (MgO) is also 1. Since the coefficients are both 1, the molar ratio is 1:1.
Therefore, the molar ratio of oxygen (O2) to magnesium oxide (MgO) in the chemical equation is 1:1.
To determine the molar ratio of oxygen to magnesium oxide in the chemical equation 2Mg + O2 -> 2MgO, we need to compare the coefficients of the oxygen molecules (O2) and magnesium oxide (MgO).
In this equation, the coefficient in front of O2 is 1, while the coefficient in front of MgO is also 1. This means that the molar ratio of O2 to MgO is 1:1.
To show this in more detail, we can break it down as follows:
- For every 2 moles of magnesium (2Mg), we have 1 mole of O2.
- And for every 2 moles of magnesium oxide (2MgO), we also have 1 mole of O2.
Therefore, the molar ratio of oxygen (O2) to magnesium oxide (MgO) in the chemical equation is 1:1.