A body of mass 10kg initially at rest is subjected to a force of 20N for 1 second.calculate the change in kinetic energy during that time ?

No opposing force?

F=ma
a=20/10 = 2m/s

vf=vi+at=2*1 m/s

To calculate the change in kinetic energy, we can use the formula:

Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic Energy

Since the body is initially at rest, its initial kinetic energy is 0. The final kinetic energy can be calculated using the formula:

Final Kinetic Energy = 1/2 * mass * velocity^2

To find the final velocity, we need to use Newton's second law of motion:

Force = mass * acceleration

Thus,

acceleration = Force / mass

acceleration = 20N / 10kg

acceleration = 2 m/s^2

Since the body is initially at rest, its initial velocity is 0. Given that the force is applied for 1 second, the final velocity can be calculated using the equation of motion:

final velocity = initial velocity + (acceleration * time)

final velocity = 0 + (2 m/s^2 * 1s)

final velocity = 2 m/s

Substituting the values into the formula for final kinetic energy:

Final Kinetic Energy = 1/2 * 10kg * (2 m/s)^2

Final Kinetic Energy = 10J

Therefore,

Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic Energy

Change in Kinetic Energy = 10J - 0 J

Change in Kinetic Energy = 10J

The change in kinetic energy during that time is 10 Joules.

To calculate the change in kinetic energy, we need to use the formula:

Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic Energy

1. Let's find the final kinetic energy:
- We know that the body is initially at rest, so the initial velocity, u, is 0 m/s.
- We also know the mass of the body, m, is 10 kg.
- The final velocity, v, can be calculated using Newton's second law: F = ma, where F is the force and a is the acceleration.
- Given force, F = 20 N
- Using Newton's second law, a = F/m = 20/10 = 2 m/s²
- We can use the equation of motion: v = u + at
- Plugging in the values, v = 0 + 2 * 1 = 2 m/s
- The final kinetic energy, KE_final, can be calculated using the formula: KE = (1/2)mv²
- Plugging in the values, KE_final = (1/2) * 10 * (2)² = 20 Joules

2. Now, let's find the initial kinetic energy:
- Since the body is initially at rest, the initial kinetic energy, KE_initial, is 0 Joules.

3. Finally, let's calculate the change in kinetic energy:
- Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic Energy
- Plugging in the values, Change in Kinetic Energy = 20 - 0 = 20 Joules

So, the change in kinetic energy during the one-second interval is 20 Joules.