1.) The initial velocity of l playing luksong tinik has horizontal and vertical components that are equal in magnitude. What angle does his velocity make with the horizontal?

Pls asap.

very close to PI/4 radians.

thanks

To find the angle that the velocity makes with the horizontal, we can use the trigonometric relationship between the horizontal and vertical components of the velocity.

Given that the horizontal and vertical components are equal in magnitude, we can call this magnitude "v" (for velocity). Let's denote the angle that the velocity makes with the horizontal as θ.

Using trigonometry, we know that the horizontal component is given by v * cos(θ), and the vertical component is given by v * sin(θ).

Since the horizontal and vertical components are equal, we can set them equal to each other:

v * cos(θ) = v * sin(θ)

Dividing both sides of the equation by v:

cos(θ) = sin(θ)

Now, we can use the trigonometric identity that relates sine and cosine:

tan(θ) = sin(θ) / cos(θ)

Since sin(θ) / cos(θ) = 1, the tangent of the angle θ is 1.

To find the angle, we take the inverse tangent (or arctan) of both sides:

θ = arctan(1)

The arctan(1) is a special angle, known as 45 degrees or π/4 radians.

Therefore, the angle that the velocity makes with the horizontal in playing luksong tinik is 45 degrees or π/4 radians.