calculus

How does 0-(1/81)-((te^9t)/81)+(9e^9t/81)=(-1/81)-0+0? Where does the 0 come from?

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asked by KKK
  1. Hmmm. Some context would be nice.
    if t=0 then ((te^9t)/81) = 0
    But (9e^(9t)/81) = (9*1)/81 = 1/9

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