An aquarium tank is built as a cylinder with a radius of 10 ft and a height of 12 feet. If the water weighs 62.43 lb per cubic foot, what is the weight of the water in the aquarium when it is full of water? Use 3.14 for pi and round to the nearest pound.
pi r^2 h * 62.43
Volume = π r^2 h = 3.14 * 10^2 * 12
weight = V * 62.43
To find the weight of the water in the aquarium, we first need to calculate the volume of the water and then multiply it by the weight per cubic foot.
The formula for the volume of a cylinder is V = π * r^2 * h, where V represents volume, π is a mathematical constant (approximately 3.14), r is the radius of the cylinder, and h is the height of the cylinder.
Plugging in the given values, we have:
V = 3.14 * (10 ft)^2 * 12 ft
V = 3.14 * 100 ft^2 * 12 ft
V ≈ 3.14 * 1200 ft^3
V ≈ 3768 ft^3
Now that we have the volume, we can find the weight of the water by multiplying it by the weight per cubic foot, which is given as 62.43 lb/ft^3.
Weight = V * weight per cubic foot
Weight = 3768 ft^3 * 62.43 lb/ft^3
Weight ≈ 235,130.04 lb
Therefore, when the aquarium is full of water, the weight of the water is approximately 235,130 pounds.