A plane flies 505 kilometers with a bearing of 316° (clockwise from north) from Naples to Elgin. The plane then flies 770 kilometers from Elgin to Canton (see figure in the link below). Canton is due west of Naples. Find the bearing of the flight from Elgin to Canton. (Round to the nearest whole number.)

www.webassign.net/larpcalclim2/6-1-048-alt.gif

You fly a HEADING, not a Bearing

You sight a bearing toward something from you.
( mathematicians drive me nuts)
NE = 505
EC = 770
360 - 316 = 54 W of N so ENC = 90 - 54 = 36 deg
sin ECN / 505 =sin 36/770
sin ECN = .588 (505/770) = .385
ECN = 22.7 deg
that is your desired heading south of west from E to C
270 - 23 = 247 deg

thanks damon, but which one is the final answer 22.7degrees or 22.7degrees

west - 22.7 = west - 23 to whole number = 270-23 = 247 deg clockwise from North

ok thanks

22.7 would be just 22.7 degrees East of North :), off into the bleak ocean.

360-316 = 44o W. of N.

Cos44 = h/505.
h = 363 km.

Cos A = 363/770.
A = 62o W. of S. = 242o CW from +y-axis = Bearing(Heading) from Elgin to Canton.

To find the bearing of the flight from Elgin to Canton, we can use the concept of relative bearings.

First, let's find the bearing of the flight from Elgin to Naples. Since Canton is due west of Naples, the bearing from Naples to Canton is 270° (measured clockwise from north). Since the plane flew from Naples to Elgin, we need to subtract 180° from the bearing of the flight from Naples to Canton:

270° - 180° = 90°

Therefore, the bearing of the flight from Elgin to Canton is 90°.

In summary, the bearing of the flight from Elgin to Canton is 90°.