What is the net ionic equation for the reaction of formic acid and methylamine
Methyl Amine & water coordinate to form methylammonium hydroxide (H₃CNH₃OH), a weak base (Kₐ =2.3 x 10ˉ¹¹) that ionizes ~0.6% as a 0.10M solution in deionized water as follows…
H₃CNH₂ + H₂O => H₃CNH₃OH < = > H₃CNH₃⁺ + OHˉ
Formic acid is a weak acid (Kₐ = 1.8 x 10ˉ⁴) that ionizes ~0.4% as 0.10M solution in deionized water. HCO₂H < = > H⁺ + C₂OHˉ
In an acid/base reaction, both compounds are weak electrolytes and react to give the salt methyl ammonium formate and water as follows…
HCO₂H + H₃CNH₃OH => H₃CNH₃⁺CO₂Hˉ + H₂O
Since formic acid, methyl ammonium hydroxide and water are weak electrolytes with very low percent ionizations, the weak electrolytes, by convention, are not shown in ionic form when writing the ionic equation. Only the salt is illustrated as ionized (salts ionize 100%)**.
Ionic Equation & Net Ionic Equation*:
HCO₂H + H₃CNH₃OH => H₃CNH₃⁺ + CO₂Hˉ + H₂O
*Since the ionic equation does not have any spectator ions then it is also the Net Ionic Equation.
**Subnote => Not all salts have the same solubility, but whatever goes into solution, ionizes 100%.
Hope this helps. Doc
Methylamine is a stronger nucleophile than the oxygen associated with formic acid and the carbon of formic acid is a good electrophile. So here is my guess:
Formic acid + methylamine ---> Formamide + water
CH2O2 + CH3NH2 ---> CH3NO + H2O
To determine the net ionic equation for the reaction between formic acid (HCOOH) and methylamine (CH3NH2), we first need to write the balanced chemical equation.
The chemical equation for the reaction between formic acid and methylamine can be written as:
HCOOH + CH3NH2 -> CH3NH3+ + HCOO-
To write the net ionic equation, we need to identify the spectator ions. Spectator ions are ions that do not participate in the reaction and remain unchanged throughout. In this reaction, the spectator ion is the chloride ion (Cl-) since it does not undergo any chemical changes.
So, the net ionic equation for the reaction between formic acid and methylamine is:
HCOOH(aq) + CH3NH2(aq) -> CH3NH3+(aq) + HCOO-(aq)
In this net ionic equation, we remove the spectator ion (Cl-) since it does not participate in the reaction. The remaining ions, HCOOH, CH3NH2, CH3NH3+, and HCOO-, represent the actual substances that are involved in the chemical change.
I apologize that is correct. The answer was in the question:
Methylamine is a weak base, so it will form an ionic bond with formic acid, as Doc 48 has mentioned, becoming positively charged by extracting a hydrogen from formic acid which becomes negatively charged. I was and still am looking at it from a simple O-chem problem.
doesn't anyone use google before coming here?
Many hits, including an old Jiskha problem.