Math

Two pumps are filling a pool. One of them is high power and can fill the pool alone in 2 hours less time than the other can do so. Given that, working together, both pumps can fill the pool in 144 minutes, how long, in hours, will it take the powerful pump to fill the pool alone?

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asked by ???
  1. 1/x + 1/(x-2) = 60/144
    now just solve for x

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    posted by oobleck
  2. s = smaller pump fill time ; b = bigger pump fill time

    s = b + 120

    (144 / s) + (144 / b) = 1

    [144 / (b + 120)] + (144 / b) = 1

    144 b + 144 b + (144 * 120) = b (b + 120)

    0 = b^2 - 168 b - 17280

    convert answer to hours

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    posted by R_scott
  3. The answer is 4 hours

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