A thin straight wire carries a current of 10 mA and makes an angle of 60° with a constant magnetic field of magnitude 10^-6 T. The portion of the wire in this field has a length of 10 cm. Calculate the magnitude of the force on this segment of the wire
A straight wire is placed in a uniform magnetic field of magnitude 0.010 T. The direction of the field makes an angle of 30° with that of the wire, which carries a current of 10 A. What is the magnitude of the force on a 1.0 m segment of the wire?
Force=current*B*Length*sinTheta whereTheta is the angle between B and current. http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/forwir2.html
To calculate the magnitude of the force on the segment of wire, we can use the formula:
F = I * L * B * sin(θ)
Where:
F is the force on the wire segment,
I is the current,
L is the length of the wire segment,
B is the magnitude of the magnetic field, and
θ is the angle between the wire and the magnetic field.
First, let's convert the current to amperes:
10 mA = 10 * 10^(-3) A = 0.01 A
Next, let's convert the length of the wire segment to meters:
10 cm = 10 * 10^(-2) m = 0.1 m
Now we can substitute the given values into the formula:
F = 0.01 A * 0.1 m * 10^(-6) T * sin(60°)
To calculate the sine of 60°, we use a scientific calculator or refer to a trigonometric table.
sin(60°) = √3 / 2 ≈ 0.866
Substituting this value into the formula:
F ≈ 0.01 A * 0.1 m * 10^(-6) T * 0.866
Simplifying the expression:
F ≈ 10^(-8) N
Therefore, the magnitude of the force on the segment of wire is approximately 10^(-8) Newtons.