a line of regression y =-1.240 +7.07x is the best fit line for a set of data comparing airfare with 30 days notice and one-day notice. find the best-predicted cost of a ticket purchased one day in advance given that the cost of the ticket is $300 if purchased 30 days in advance of the flight.

a $475 b.$3361 c.$881 d.$133

To find the best-predicted cost of a ticket purchased one day in advance, we can substitute the given information into the equation of the regression line: y = -1.240 + 7.07x.

First, let's assign the variables:
x = number of days in advance
y = cost of ticket

We are given that the cost of the ticket is $300 if purchased 30 days in advance, so we can substitute this value into the equation. Let x = 30 and y = 300.

y = -1.240 + 7.07x
300 = -1.240 + 7.07(30)

Now, we will solve for the x-value when y = 300:

300 = -1.240 + 7.07x
301.24 = 7.07x
x ≈ 42.5

Since we are interested in finding the predicted cost of a ticket purchased one day in advance (x = 1), we can substitute this value into the equation:

y = -1.240 + 7.07(1)
y = -1.240 + 7.07
y ≈ 5.83

Therefore, the best-predicted cost of a ticket purchased one day in advance is approximately $5.83. However, none of the given answer choices match this result accurately, so it seems there might be an error or inaccuracy in the provided options.

To find the best-predicted cost of a ticket purchased one day in advance, we can substitute the given values into the equation of the regression line.

Given:
Regression line equation: y = -1.240 + 7.07x
Cost of the ticket purchased 30 days in advance (x) = $300

Let's calculate the predicted cost (y) for one day in advance (x = 1):

y = -1.240 + 7.07(1)
y = -1.240 + 7.07
y = 5.83

Therefore, the best-predicted cost of a ticket purchased one day in advance is approximately $5.83. However, this answer does not match any of the provided options, so please check if there are any errors in the question or the answer choices.

well, just plug in x=300 and calculate y.