A circular path 3 feet wide has an inner diameter of 450 feet. How much farther is it around the outer edge of the path than around the inner edge? Round to nearest hundredth. Use 3.14 for π.
A circular path 3 feet wide has an inner diameter of 750 feet. How much farther is it around the outer edge of the path than around the inner edge?
A circular path 3 feet wide has an inner diameter of 750 feet. How much farther is it around the outer edge of the path than around the inner edge?
To find the difference in distance between the outer edge and the inner edge of the circular path, we need to calculate the circumference of each edge.
First, let's find the radius of the inner circle. The diameter is given as 450 feet, so the radius is half of that: 450 / 2 = 225 feet.
The outer radius is the sum of the inner radius and the width of the circular path: 225 + 3 = 228 feet.
To find the circumference of a circle, we use the formula C = 2πr, where C is the circumference and r is the radius.
For the inner edge:
C_inner = 2 * 3.14 * 225
For the outer edge:
C_outer = 2 * 3.14 * 228
Now, let's calculate the circumferences:
C_inner = 2 * 3.14 * 225 = 1413 feet (rounded to the nearest foot)
C_outer = 2 * 3.14 * 228 = 1432.64 feet (rounded to the nearest hundredth)
To find the difference in distance, we subtract the inner circumference from the outer circumference:
Difference = C_outer - C_inner = 1432.64 - 1413 = 19.64 feet (rounded to the nearest hundredth).
Therefore, the the outer edge of the circular path is approximately 19.64 feet farther than the inner edge.
thanks
since 3 feet is added to the radius, 6 feet is added to the diameter.
456pi - 450pi = 6pi