Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played?
To write the inequality representing the possible number of games that can be played with $10, we need to consider that admission into the carnival costs $3 and each game costs $0.25. Let's denote the number of games as "x".
The cost of admission is a fixed expense of $3.
The cost of playing each game is $0.25, so the total cost of playing "x" games would be 0.25x.
To find the maximum number of games that can be played with $10, we need to determine the value of "x" that satisfies the inequality.
The total cost (admission plus games) cannot exceed $10, so the inequality can be written as:
3 + 0.25x ≤ 10
Simplifying this inequality, we have:
0.25x ≤ 10 - 3
0.25x ≤ 7
To isolate "x", we divide both sides of the inequality by 0.25:
x ≤ 7 / 0.25
x ≤ 28
Therefore, the inequality representing the possible number of games that can be played with $10 is x ≤ 28.
The maximum number of games that can be played with $10 is 28 games.
3+.25x <= 10
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