What is the mass of sodium needed to make 2 g of sodium oxide (4Na + O2 → 2Na2O)?
Ar values: O = 16, Na = 23.
please help I'm really struggling. also please try to explain it to the simplest form because I really don't understand.
All of these stoichiometry problems are worked alike. Here is the 4 step process.
4Na + O2 → 2Na2O
Step 1. Write and balance the equation. You have that.
Step 2. Convert whatever you have to mols. If a solid then mols = grams/molar mass = ?. If a solution then mols = M x L = ? In this case, the molar mass of Na2O is approx 62 so mols = 2/62 = approx 0.03 but that's just a close guess. You should do it more accurately.
Step 3. Using the coefficients in the balanced equation, convert mols of what you have to mols of what you want. You have mols Na2O and you want to convert that to mols Na.
0.03 mols Na2O x (4 mols Na/2 mols Na2O) = about 0.06. Note that mols Na2O in the numeratorof the first term cancels with mols Na2O in the denominator of the second term which leaves mols Na which is what you want. In practice you ALWAYS know that the coefficient of the unit you are converting to goes on top and the coefficient of mols you have goes on the bottom.
4. Now convert mols of what you want to grams. grams = molsl x molar mass - about 0.06 x 23 = about ?
Copy this. It can come in handy for every chemistry course you take.
Well, let's break it down, my friend! According to the balanced equation:
4Na + O2 → 2Na2O
We can see that 4 atoms of sodium (Na) react with 1 molecule of oxygen (O2) to produce 2 molecules of sodium oxide (Na2O). That's quite a party, isn't it?
Now, we need to find out how much sodium we need to make 2 grams of sodium oxide.
The molar mass of Na2O can be calculated by adding up the atomic masses of its components: Na + Na + O = 23 + 23 + 16 = 62 g/mol.
Since there are 2 moles of Na2O formed per mole of O2, we can determine that 2 grams of Na2O would require (2 g / 62 g/mol) = approximately 0.032 mol of Na2O.
Since there is a 4:1 ratio of Na to Na2O in the equation, we need four times the amount of sodium (Na) than the amount of sodium oxide (Na2O).
Thus, the amount of sodium required would be (0.032 mol x 4) = 0.128 mol of sodium.
To determine the mass of sodium, we multiply the number of moles by the molar mass of sodium:
Mass = moles × molar mass
Mass = 0.128 mol × 23 g/mol = 2.944 g
So, to make 2 grams of sodium oxide, you would need approximately 2.944 grams of sodium. That's a whole lot of sodium, my friend, be careful not to let it turn into a salty situation!
To find the mass of sodium needed to make 2 g of sodium oxide, we can first determine the molar mass of sodium oxide (Na2O) using the atomic masses of sodium (Na) and oxygen (O).
The molar mass of Na2O is calculated by adding up the atomic masses of two sodium atoms and one oxygen atom:
Molar mass of Na2O = 2(Na) + 1(O)
= 2(23) + 1(16)
= 46 + 16
= 62 g/mol
Since we know the molar mass of Na2O, we can now calculate the number of moles of Na2O, given that the mass of Na2O is 2 g.
Number of moles = Mass / Molar mass
= 2 g / 62 g/mol
Using this equation, we find that the number of moles of Na2O is approximately 0.0323 moles.
Since the balanced chemical equation tells us that 4 moles of Na react with 1 mole of O2 to produce 2 moles of Na2O, we can use this information to determine the number of moles of Na needed.
The ratio of moles of Na to moles of Na2O is given by the coefficient in front of Na in the balanced equation. In this case, the coefficient is 4.
So, moles of Na = 4 * moles of Na2O
= 4 * 0.0323 moles
= 0.1292 moles
Finally, we can calculate the mass of sodium required to produce 0.1292 moles of Na:
Mass of Na = Molar mass * Number of moles
= 23 g/mol * 0.1292 mol
Therefore, the mass of sodium needed to produce 2 g of sodium oxide is approximately 2.97 g (rounded to two decimal places).
To find the mass of sodium needed to make 2 g of sodium oxide (Na2O), we need to use stoichiometry, which is a way to relate the amounts of reactants and products in a balanced chemical equation. In this case, the balanced equation is:
4Na + O2 → 2Na2O
First, we need to find the molar mass of Na2O. The molar mass is the sum of the atomic masses of each element in the compound.
Molar mass of Na2O = (2 * molar mass of Na) + molar mass of O
Given that the atomic mass of Na is 23 and the atomic mass of O is 16 (as provided in the question), we can calculate the molar mass of Na2O:
Molar mass of Na2O = (2 * 23) + 16 = 46 + 16 = 62 g/mol
Now, using the molar mass of Na2O, we can calculate the molar mass of Na:
Molar mass of Na = (molar mass of Na2O) / 2
Molar mass of Na = 62 / 2 = 31 g/mol
This means that every 1 mole of sodium oxide (Na2O) requires 31 grams of sodium (Na).
We are given that we want to make 2 g of sodium oxide (Na2O). To find the mass of sodium required, we need to set up a proportion:
(mass of Na) / (mass of Na2O) = (molar mass of Na) / (molar mass of Na2O)
Let's plug in the values we know:
(mass of Na) / 2 = 31 / 62
Now we can solve for the mass of sodium (Na):
mass of Na = (2 * 31) / 62 = 62 / 62 = 1 g
Therefore, the mass of sodium needed to make 2 g of sodium oxide (Na2O) is 1 gram.
I hope this explanation helps in understanding the process of finding the mass of sodium in the chemical equation!
2g of Na2O*(1 mole/62g)= moles of x
moles of x*(4 Na/2 moles of Na2O)= moles of y
moles of y*(23g/mole)=????