Balance the following equations?

Fe2O3 + 3H2 → 2Fe + 3H2O

4NH3 + 5O2  → 4NO + 6H2O

2Al + 6HAsO3  → 3H2 + 2Al(AsO3)3

They all seem balanced to me.

Those look balanced to me.

they are not i have no idea where to start.

What are you talking about? Those equations are balanced.

Look at #1, for example.
Fe2O3 + 3H2 → 2Fe + 3H2O
I see 2 Fe on the left and 2 on the right.
I see 6 H on the left and 6 on the right.
I see 3 O on the left and 3 on the right. BALANCED.
The others are the same.

To balance chemical equations, you need to make sure that the number of atoms of each element is equal on both sides of the equation. Here's how you can balance each of the equations you provided:

1. Fe2O3 + 3H2 → 2Fe + 3H2O
Let's first balance the iron atoms. There are 2 iron (Fe) atoms on the left side, so we need to have 2 iron atoms on the right side as well. We can achieve this by placing a coefficient of 2 in front of the Fe on the right side:
Fe2O3 + 3H2 → 2Fe + 3H2O

Next, let's balance the hydrogen (H) atoms. We have 6 hydrogen atoms on the right side (3 from H2 and 3 from H2O), so we need to place a coefficient of 3 in front of H2 on the left side:
Fe2O3 + 3H2 → 2Fe + 3H2O

Finally, let's balance the oxygen (O) atoms. On the left side, we have 3 oxygen atoms from Fe2O3, and on the right side, we have 3 oxygen atoms from H2O. Therefore, the equation is already balanced.

Final balanced equation:
Fe2O3 + 3H2 → 2Fe + 3H2O

2. 4NH3 + 5O2  → 4NO + 6H2O
First, let's focus on balancing the nitrogen (N) atoms. We have 4 nitrogen atoms on the left side, so we need to have 4 nitrogen atoms on the right side as well. We can achieve this by placing a coefficient of 2 in front of NO on the right side:
4NH3 + 5O2  → 4NO + 6H2O

Next, let's balance the hydrogen (H) atoms. On the left side, we have 12 hydrogen atoms (4 from NH3 and 8 from H2O). To balance this, we need to place a coefficient of 6 in front of H2O on the right side:
4NH3 + 5O2  → 4NO + 6H2O

Finally, let's balance the oxygen (O) atoms. On the left side, we have 5 oxygen atoms from O2, and on the right side, we have 6 oxygen atoms from H2O and 1 oxygen atom from NO. Therefore, we need to place a coefficient of 4 in front of O2 on the left side:
4NH3 + 4O2  → 4NO + 6H2O

Final balanced equation:
4NH3 + 4O2  → 4NO + 6H2O

3. 2Al + 6HAsO3  → 3H2 + 2Al(AsO3)3
Let's start with balancing the aluminum (Al) atoms. We have 2 aluminum atoms on the left side, so we need to have 2 aluminum atoms on the right side as well. To achieve this, we place a coefficient of 2 in front of Al(AsO3)3 on the right side:
2Al + 6HAsO3  → 3H2 + 2Al(AsO3)3

Now, let's balance the hydrogen (H) atoms. On the left side, we have 6 hydrogen atoms from HAsO3, and on the right side, we have 6 hydrogen atoms from H2. Therefore, the hydrogen atoms are already balanced.

Finally, let's balance the arsenic (As) and oxygen (O) atoms. On the left side, we have 6 arsenic atoms and 18 oxygen atoms from HAsO3, so we need to have the same number of arsenic and oxygen atoms on the right side. To achieve this, we place a coefficient of 6 in front of HAsO3 on the left side and a coefficient of 3 in front of H2 on the right side:
12Al + 6HAsO3  → 3H2 + 6Al(AsO3)3

Final balanced equation:
12Al + 6HAsO3  → 3H2 + 6Al(AsO3)3