The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grades at Lincoln Middle School. Two box and whisker plots are shown above a number line. The number line is scaled from 2 to 38 by twos. The first plot above the number line is labeled seventh grade. On the seventh grade plot: The left point is at 6. The left side of the box is at 14. The vertical segment inside the box is at 18 . The right side of the box is at 22. The right point of the plot is at 26. The eighth grade plot is above the seventh grade plot. On the eighth grade plot: The left point is at 22. The left side of the box is at 26. the vertical segment inside the box is at 30. The right side of the box is at 34. The right point of the plot is at 38.
a) Describe the overlap of the two sets of data.
b) Find the IQR of each set.
c) Find the difference between the medians of the sets.
d) What number multiplied by the IQR equals the difference between the medians of the two sets?
Here's some help. Let me know if you need any more help!
a) The ranges of the two sets of data overlap by 4.
The upper quartile of the 7th grade data equals the lowest value of the 8th grade data.
The highest value of the 7th grade data equals the lower quartile of the 8th grade data.
b) IQR of the 7th grade data = 22 - 14 = 8
IQR of the 8th grade data = 34 - 26 = 8
c) median difference = 30 - 18 = ____
d) 8*x = answer to c)
x = ____
a. the overlap is found by seeing the difference between leftmost and rightmost point.
b. the IQR for seventh grade plot is 8
the IQR for eighth grade plot is 8
c. the difference between median of the two sets is 12
d. the needed multiplied number is 1.5
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literally no clue rn help
i have no clue
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a. The ranges of the two sets of data overlap by 4
The upper quartile of the 7th-grade data equals the lowest value of the 8th-grade data
The highest value of the 7th-grade data equals the lower quartile of the 8th-grade data
b. IQR of the 7th grade data = 22 - 14 = 8
IQR of the 8th grade data = 34 - 26 = 8
c. median difference is = 30 - 18 = 12
d. 8*x = answer to c)
x = 12
I apologize for the late response. Here are the answers:
a. The overlap is found by seeing the difference between the leftmost and rightmost point.
The range of the 7th-grade data is 20 (6 - 26).
The range of the 8th-grade data is 16 (22 - 38).
Since the 8th grade data has a smaller range, the overlap is 16.
b. IQR of the 7th grade data = 22 - 14 = 8
IQR of the 8th grade data = 34 - 26 = 8
c. The difference between the median of the two sets is 30 - 18 = 12.
d. Let x be the number to be multiplied to IQR.
Then, 8x = 12.
Solving for x, we have x = 1.5.