Maths

How do we solve for x and y where y=(1/3)log2(x) and 8^(2y-1) = 2(x-4)

From the 1st one,I got x = 2^(3y) & by substituting it in the 2nd resulted 8^(2y-1) = 2((2)^(3y) - 4)

How to proceed?

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asked by Ash
  1. ok so far, but messy
    Check if the 2nd equation wasn't
    8^(2y-1) = 2^(x-4)

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    posted by Reiny
  2. Thanks Reiny I solved it

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    posted by Ash

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