the system side of an open u-tube manometer is 48 mm lower than the open side. What is the pressure of the system?
Is the pressure of the system side 48 mm higher or 48 mm lower than atmospheric pressure.
Since the mercury is higher on the open side, then the system is 48 mm higher than atmopheric pressure (48+760=808 mm Hg)
To determine the pressure of the system using an open U-tube manometer, you need to consider the difference in the fluid heights between the two sides of the manometer.
Here's how to calculate the pressure:
1. Start by measuring the height difference between the two arms of the manometer. In this case, it is given that the system side is 48 mm lower than the open side.
2. Understand that the pressure difference between the two sides of the manometer is caused by the weight of the fluid column. The pressure on the open side is equal to the atmospheric pressure since it is open to the air.
3. Use the equation P = ρgh, where P represents the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height difference between the two sides of the manometer.
4. The density of the fluid depends on what fluid is being used. Typically, a common fluid used in manometers is mercury (Hg). For mercury, the density is approximately 13,600 kg/m³.
5. Convert the height difference from millimeters to meters by dividing it by 1000 (since there are 1000 millimeters in a meter).
6. Plug in the values into the equation P = ρgh. In this case, let's assume that the acceleration due to gravity (g) is 9.8 m/s², and the height difference (h) is 48 mm / 1000 = 0.048 m.
7. Calculate the pressure: P = (13,600 kg/m³) * (9.8 m/s²) * (0.048 m) = 6,363.36 Pa (Pascal).
Therefore, the pressure of the system is approximately 6,363.36 Pascal.