A wooden block of weight 24N lies on a horizontal table,when a force of 12N was applied to the block,it takes the block to "just slide "what is the coefficient of static friction between the block and the table
12N/24N = 0.50
To find the coefficient of static friction between the block and the table, we need to consider the forces acting on the wooden block and determine the conditions for it to just start sliding.
First, let's analyze the forces acting on the block:
1. Weight (W): The weight of the block is given as 24N. This force acts vertically downwards.
2. Applied Force (F): A force of 12N is applied horizontally to the block in an attempt to make it slide.
3. Normal Force (N): The normal force is the force exerted by the table on the block perpendicular to the surface. In this case, it is equal to the weight of the block, which is 24N.
Now, for the block to remain in equilibrium and not slide, the force of static friction (Fs) must be equal to the applied force (F). The force of static friction can be calculated using the equation:
Fs = coefficient of static friction (μ) * Normal force (N)
Therefore, we have:
Fs = μ * N
Since the block just starts to slide when the applied force is equal to the force of static friction, we can write:
F = μ * N
Substituting the given values:
12N = μ * 24N
Now, we can solve for the coefficient of static friction (μ):
μ = 12N / 24N
μ = 0.5
Therefore, the coefficient of static friction between the block and the table is 0.5.