If g(x)=(ax square root of 1-x)^2. Express g(10) in simplest form
I did g(10)=(a(10) square root 1-10)^2= (a*10)^2(1-10)=1000^2(-9)=
-9000^2
Is this correct? thanks for checking my work
If your expression mean:
g = a ∙ x ∙√ ( 1 - x )²
then
g(10) = a ∙ 10 ∙ √ ( 1 - 10 )² = 10 a ∙ √ ( - 9 )² = 10 a ∙ ( - 9 ) = - 90 a
g = [ a ∙ x ∙√ ( 1 - x ) ]²
then
g = [ a ∙ 10 ∙√ ( 1 - 10 ) ]² =
[ 10 a ∙√- 9 ) ]² =
( 10 a ∙ 3 i ² )=
(30 a ∙ i )² =
30² ∙ a² ∙ i² =
900 ∙ a² ∙ ( - 1 ) = - 900 ∙ a²
My typo
not
( 10 a ∙ 3 i ² )=
correct is
( 10 a ∙ 3 i )² =
yes , it was the second one and when I looked over it again I saw that I actually wrote 100a^2 on my paper but when I put in the question here I did 1000, I can't read my own handwriting. Thank you for explaining both ways.
To express g(10) in simplest form, let's go step by step.
We are given the function g(x) = (ax√(1-x))^2.
To find g(10), we substitute x with 10 in the function:
g(10) = (a(10)√(1-10))^2
Now, let's simplify this expression:
√(1-10) = √(-9)
The square root of a negative number is not defined in the real number system, so we cannot calculate this term further.
Therefore, we cannot simplify g(10) any further, and the expression remains g(10) = (a(10)√(1-10))^2.
It seems that there may be an error in the calculation you provided. Please double-check the problem statement or your calculations.