From the molecular equation find the overall ionic and net ionic:
Molecular: H3PO4 (aq) + 3NaOH (aq) --> Na3PO4 (aq) + 3H2O (l)
To find the overall ionic equation and net ionic equation from the given molecular equation, we need to first write out the full ionic equation.
The molecular equation is:
H3PO4 (aq) + 3NaOH (aq) --> Na3PO4 (aq) + 3H2O (l)
To write the full ionic equation, we need to separate all the soluble compounds into their respective ions.
H3PO4 (aq) ionizes into H+ and PO4^-3 ions.
NaOH (aq) ionizes into Na+ and OH- ions.
Na3PO4 (aq) dissociates into Na+ and PO4^-3 ions.
The full ionic equation can be written as follows:
3H+ (aq) + PO4^-3 (aq) + 3Na+ (aq) + 3OH- (aq) --> Na+ (aq) + PO4^-3 (aq) + 3H2O (l)
Next, to find the net ionic equation, we remove the spectator ions (ions that appear on both sides of the equation). In this case, the Na+ and PO4^-3 ions are spectator ions.
The net ionic equation is:
3H+ (aq) + 3OH- (aq) --> 3H2O (l)
So, the overall ionic equation is 3H+ (aq) + PO4^-3 (aq) + 3Na+ (aq) + 3OH- (aq) --> Na+ (aq) + PO4^-3 (aq) + 3H2O (l) and the net ionic equation is 3H+ (aq) + 3OH- (aq) --> 3H2O (l).
To find the overall ionic and net ionic equations from the given molecular equation, we need to first understand the species involved and their respective charges.
The molecular equation is as follows:
H3PO4 (aq) + 3NaOH (aq) --> Na3PO4 (aq) + 3H2O (l)
In the molecular equation, H3PO4 represents phosphoric acid, and NaOH represents sodium hydroxide.
To determine the overall ionic equation, we need to separate the compounds into their respective ions. We can do this by breaking apart the soluble compounds into their ions and leaving the insoluble compounds unchanged.
The soluble compounds in this reaction are H3PO4, NaOH, and Na3PO4. They dissociate into their respective ions when dissolved in water.
H3PO4 (aq) --> H+ (aq) + H+ (aq) + H+ (aq) + PO4^3- (aq)
NaOH (aq) --> Na+ (aq) + OH- (aq)
Na3PO4 (aq) --> 3Na+ (aq) + PO4^3- (aq)
The insoluble compound, H2O, remains unchanged.
Overall Ionic Equation:
H+ (aq) + H+ (aq) + H+ (aq) + PO4^3- (aq) + 3Na+ (aq) + 3OH- (aq) --> 3Na+ (aq) + PO4^3- (aq) + 3H2O (l)
To determine the net ionic equation, we remove the spectator ions that are present on both sides of the equation. In this case, H+ and Na+ are spectator ions.
Net Ionic Equation:
3OH- (aq) + H+ (aq) --> 2H2O (l)
So, the overall ionic equation is H+ (aq) + H+ (aq) + H+ (aq) + PO4^3- (aq) + 3Na+ (aq) + 3OH- (aq) --> 3Na+ (aq) + PO4^3- (aq) + 3H2O (l), and the net ionic equation is 3OH- (aq) + H+ (aq) --> 2H2O (l).
Net ionic:
3H+ 3OH>>>3H2O
overall ionic:
3H+ + PO4--- + 3Na+ + 3OH- >>3Na + 3 PO4--- + 3H2O(l)