Math

if sin theta =1/2 and cos theta= √(3)/2. find tha values of tan θ, cot θ, sec θ and cscθ.

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  1. can someone show me the answer to tanθ and cotθ
    my answer to secθ is 2/√3 and cscθ is 2

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  2. Both sin theta and cos theta are positive, so theta must be in quad I
    construct your right-angled triangle with opposite as 1 and hypotenuse as 2
    and use Pythagoras to find the adjacent to be √3 .
    So now simply use the definitions of the trig ratios to find the other 4 missing ratios.

    eg sec theta = hypotenuse/adjacent = 2/√3

    btw, memorize SOH CAH TOA

    let me know what you get

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    posted by Reiny
  3. my answers are
    secθ is 2/√3
    cscθ is 2
    i really don't know how to get tanθ and cot θ

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  4. the tanθ is 22.20
    cot θ is 1/22.20

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  5. How can you possibly come up with those numbers ?? They are not even sides of the triangle.
    the others are correct

    tan θ = opp/adj = 1/√3 and cot θ = √3

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    posted by Reiny
  6. i did tan^-1 ((1/2)/(√(3)/2)) on my calculator

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  7. tan^-1 ((1/2)/(√(3)/2)) would have given you the angle

    Of course that angle would obviously be 30 degrees, not 22.2

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    posted by Reiny
  8. sin A = 1/2 = Y/r.
    Cos A = sqrt3/2 = X/r.
    x = sqrt 3, Y = 1, r = 2.

    Tan A = Y/X = 1/sqrt3.
    Cot A = 1/Tan A = sqrt3/1 = sqrt 3.
    sec A = 1/Cos A = 2/sqrt 3.
    csc A = 1/sin A = 2/1 = 2.

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    posted by henry2,

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