
 👍 0
 👎 0
posted by oobleck
Respond to this Question
Similar Questions

calculus review please help!
1) Find the area of the region bounded by the curves y=arcsin (x/4), y = 0, and x = 4 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative. 2)Set up, but do not evaluate,
asked by Danni on March 22, 2017 
calculus
1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x+3). Show the integral used, the limits of integration and how to evaluate the integral. 2. Find the area of the region bounded by x=y^2+6, x=0 , y=6, and y=7.
asked by katarina on May 15, 2012 
calculus
using the method of shells, set up, but don't evaluate the integral, an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. Y=e^x, x=0, y=2, about y=1
asked by marks on March 16, 2014 
calc 3
1. Evaluate the given integral by making an appropriate change of variables, where R is the region in the first quadrant bounded by the ellipse 36x^2+25y^2=1. L= double integral R (4sin(144x^2+100y^2) dA. 2. Use the given
asked by lala on November 4, 2014 
Calculus
Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = 3 I got the integral from 1 to 2.718 of pi(1)^2pi(ln(x))^2 Is
asked by Kait on March 19, 2018 
Calculus check
The functions f and g are given by f(x)=sqrt(x^3) and g(x)=162x. Let R be the region bounded by the xaxis and the graphs of f and g. A. Find the area of R. B. The region R from x=0 to x=4 is rotated about the line x=4. Write,
asked by Anonymous on April 16, 2015 
Calculus
Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 2, and x = 1 is revolved around the line y = −2.
asked by Jared on May 18, 2017 
calculus
Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = −3.
asked by Anonymous on April 16, 2015 
Calculus
Use the shell method to set up, but do not evaluate, an integral representing the volume of the solid generated by revolving the region bounded by the graphs of y=x^2 and y=4xx^2 about the line x=6. I had the shell radius as
asked by Ryan on March 7, 2011 
Calculus Please Check my answer
Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = 1. ANSWER: v = ∫[1,e] π(4(lnx+1)^2) dx
asked by Dloc on May 2, 2017