I am thinking of a six-digit number. One of the digits (not the first!) is a zero. There is a 3 to the left of a one. There is a 7 to the right of a 9. There is a 5 to the left of a 3. If the first three digits minus the last three digits is equal to 665, what is my six-digit number?

I got 975310; is this right?

you are correct

now dab

Ok sure......

To solve this problem, we can follow these steps:

Step 1: Analyze the given information and make a list of all the clues:
- The number is six-digit.
- One of the digits (not the first!) is zero.
- There is a 3 to the left of a 1.
- There is a 7 to the right of a 9.
- There is a 5 to the left of a 3.
- The difference between the first three digits and the last three digits is 665.

Step 2: Deduce the possible positions for each digit based on the given clues:
Based on the given information, we can deduce the following:
- The thousands digit must be 9 because there is a 7 to its right.
- The ones digit must be 1 because there is a 3 to its left.
- The tens digit must be 3 because there is a 5 to its left.
- Since the first three digits minus the last three digits is equal to 665 and the thousands, ones, and tens digits are already placed, we can deduce the ordering of the remaining digits.

Step 3: Arrange the remaining digits:
- With the information we have so far, the possible ordering of digits is: _ _ 9 7 5 3.

Step 4: Check the clues and find the missing digit:
- Since one of the digits (not the first!) is zero, we need to place it in one of the first three positions.
- By analyzing the clues, we deduce that the hundreds digit must be 0.

Step 5: Verify the solution:
- Now that we have arranged all the digits based on the clues, assemble the digits together to form the six-digit number: 903753.

Therefore, the correct six-digit number that satisfies all the given clues is 903753.