You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?
20
24
48
120
I think its A im not to sure
it is 120
you (1) AND 4 friends
what is 1+4
5
what is 5! (5*4*3*2*1)
120
Math has been known for its trickery. I believe that you are included as a fifth friend. So I believe it is 120.
so
what is the answer?
5 people, so
1st seat: 5 choices
2nd seat: 4 choices
...
for a total of 5*4*3*2*1 = 120 ways to sit
that answer is so wrong.
You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?
bot?
This is a combinatorial problem. The number of ways you and 4 friends can sit in assigned seats can be calculated using permutations.
The answer is 120.
This can be calculated as follows:
There are 5 people in total, so the first seat can be filled by any of the 5 people.
Once the first seat is filled, there are only 4 people left that can fill the second seat.
After the second seat is filled, there are only 3 people left that can fill the third seat.
After the third seat is filled, there are only 2 people left that can fill the fourth seat.
Lastly, there is only 1 person left that can fill the fifth seat.
Therefore, the total number of ways you and 4 friends can sit in assigned seats is:
5 x 4 x 3 x 2 x 1 = 120.
So, the answer is 120.
To determine the number of different ways you and your friends can sit in the assigned seats, you need to use the concept of permutations.
Permutations are arrangements of objects where the order matters. In this case, the order of your friends sitting in the assigned seats matters.
Since there are 5 people (you and your 4 friends), and each person can sit in one assigned seat, you have 5 choices for the first seat, 4 choices for the second seat, 3 choices for the third seat, 2 choices for the fourth seat, and 1 choice for the fifth seat.
To find the total number of permutations, you multiply all the choices together:
5 * 4 * 3 * 2 * 1 = 120
Therefore, the answer is 120, which corresponds to option D.
The answer is 24
There are 24 possible permutations for these 4 items.
For n items, there are n! (n factorial) ways of arranging them, when the order of your arrangements matters.
n!=n × (n-1) × (n-2) × ... 1. Here 4!=4 × 3 × 2 × 1 = 24.
Here are the possible permutations:
1: 1 2 3 4
2: 1 2 4 3
3: 1 3 2 4
4: 1 4 2 3
5: 1 3 4 2
6: 1 4 3 2
7: 2 1 3 4
8: 2 1 4 3
9: 3 1 2 4
10: 4 1 2 3
11: 3 1 4 2
12: 4 1 3 2
13: 2 3 1 4
14: 2 4 1 3
15: 3 2 1 4
16: 4 2 1 3
17: 3 4 1 2
18: 4 3 1 2
19: 2 3 4 1
20: 2 4 3 1
21: 3 2 4 1
22: 4 2 3 1
23: 3 4 2 1
24: 4 3 2 1