A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jack picks a fruit at random and does not replace it. Then Bethany picks a fruit at random. What is the probability that Jack gets a peach and Bethany gets an orange?

10/27
5/91
5/98
93/182
I think its D.

5/14 * 2/13 = 5/(7*13) = 5/91

thx a bunch!! :)

You are welcome.

To find the probability that Jack gets a peach and Bethany gets an orange, we first need to find the total number of possible outcomes and the number of favorable outcomes.

Total number of possible outcomes:
The total number of fruits in the basket is 3 apples + 2 oranges + 2 bananas + 2 pears + 5 peaches = 14. Since Jack picks a fruit first, there are 14 possible outcomes for Jack.

Number of favorable outcomes:
Since Jack picks a peach, there are 5 peaches to choose from. After Jack picks a fruit, there are now 13 fruits left in the basket. Among those remaining fruits, there are 2 oranges. So the number of favorable outcomes for Bethany is 2.

Probability:
The probability of an event is given by the formula:
Probability = Number of favorable outcomes / Total number of possible outcomes

In this case, the number of favorable outcomes is 5 (Jack picking a peach) multiplied by 2 (Bethany picking an orange) = 10. The total number of possible outcomes is 14 (Jack picking any fruit). Therefore, the probability is 10/14 or simplifying it further, 5/7.

So, the answer is actually 5/7, which is not one of the options given. It seems there might be a mistake in the given options, or the correct answer is not included.