A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?
20/43
40/43
20/1849
96/1849
I think its B
if you replaced it your events are independent
8/43 * 12/43 = 96/1849
p red = 9/41
replace so independent
p blue = 10/41
9/41 * 10/41 = 90/1681
Thx Damon
You are welcome.
P(red) = 8/43
P(blue) = 12/43
multiply the two probabilities (independent events)
To find the probability of choosing a red marble first and then a blue marble, we need to calculate the individual probabilities and multiply them together.
Step 1: Calculate the probability of choosing a red marble first.
There are a total of 5 + 8 + 11 + 7 + 12 = 43 marbles in the bag. Since there are 8 red marbles, the probability of choosing a red marble first is 8/43.
Step 2: Calculate the probability of choosing a blue marble next.
After choosing a marble and replacing it, there are still 43 marbles in the bag. However, since we put the first marble back, the number of blue marbles remains the same at 12. So the probability of choosing a blue marble second is 12/43.
Step 3: Multiply the probabilities together.
To find the probability of both events happening, we multiply the probabilities from Step 1 and Step 2. Thus, P(red, then blue) = (8/43) * (12/43) = 96/1849.
Therefore, the correct answer is D) 96/1849.