find the voltage across each resistor in series.
E=15v
There are three resistors:
R, 2R, 4R
Note: R is the lowest value and all others are multiples of that value as indicated.
Note to anyone who is doing this question: there was NO picture given
total resistance is 7R
so, the voltage drop across each resistor is
15(R/7R) = 15/7
15(2R/7R) = 30/7
15(4R/7R) = 120/7
Note that the total voltage drop across the circuit is 15V. Each resistor gets its share of the whole 7R ohms
I = E/7R = 15/7R.
V1 = I*R = 15/7R * R = 15/7 = 2.14 Volts.
V2 = I*2R = 15/7R * 2R = 30/7 = 4.29 Volts.
V3 = I*4R = 15/7R * 4R = 60/7 = 8.57 Volts.
To find the voltage across each resistor in a series circuit, you need to determine the voltage drop across each individual resistor. In a series circuit, the total voltage provided by the battery or power source is divided among the resistors based on their respective resistance values.
In this case, the total voltage provided by the battery is E = 15V. The resistors have values R, 2R, and 4R.
To find the voltage across each resistor, you can use Ohm's Law, which states that V = I * R, where V is the voltage, I is the current, and R is the resistance.
In a series circuit, the current flowing through each resistor is the same. Therefore, to find the voltage across each resistor, we need to calculate the current flowing through the circuit.
The total resistance in a series circuit is the sum of the individual resistances: R_total = R + 2R + 4R = 7R.
Using Ohm's Law, we can determine the current flowing through the circuit:
V = I * R_total
15V = I * 7R
I = 15V / 7R
With the current value, you can now find the voltage drop (V) across each resistor using Ohm's Law:
Voltage across the first resistor (R):
V_R1 = I * R = (15V / 7R) * R
Voltage across the second resistor (2R):
V_R2 = I * (2R) = (15V / 7R) * (2R)
Voltage across the third resistor (4R):
V_R3 = I * (4R) = (15V / 7R) * (4R)
Simplifying these expressions will give you the voltage across each resistor.