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Integrate: f (x)/(2x + 1) dx let f represent integrate sign let u = x, du = dx => dx = du = f (u)/(2u + 1) du = f u (2u + 1)^(1) du = (1/2)u^2 (ln2u + 1) + c = (1/2)x^2 (ln2x + 1) + c ...what did I do wrong? The correct
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