2. According to Coulomb’s Law, what is the change of force between two electrically charged bodies when the distance between them is increased by 3 times?
a. Decrease 9 times
b. Increase 3 times
c. Decrease 3 times
d. Increase 9 times
since F=*/d^2, changing d to 3d makes the denominator (3d)^2 = 9d^2
So, A
To determine the change in force between two electrically charged bodies when the distance between them is increased by 3 times, we can refer to Coulomb's Law. Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically, Coulomb's Law can be expressed as:
F = k * (q1 * q2) / r^2
Where:
F is the force between the two charged bodies,
k is the electrostatic constant,
q1 and q2 are the charges of the bodies, and
r is the distance between the bodies.
In this case, we need to compare the change in force when the distance is increased by 3 times. Let's assume that the initial distance between the bodies is represented by r1, and the new distance, after increasing by 3 times, is represented by r2.
From the formula, we can see that the force is inversely proportional to the square of the distance. Therefore, if the distance becomes 3 times larger (r2 = 3 * r1), then the square of the distance becomes 9 times larger (r2^2 = (3 * r1)^2 = 9 * r1^2).
Since the force is inversely proportional to the square of the distance, increasing the distance by 3 times will cause the force to decrease by 9 times.
Therefore, the correct answer is:
a. Decrease 9 times