Triangle ABC has <BAC=46° and <ABC=54°. An altitude (perpendicular line) is drawn from C to meet AB at point D. If the altitude is 5.3cm long, find, correct to 1 d.p. the length of:
a) AC
Just require help drawing the diagram.
Don't think you read the part where I needed help drawing the diagram, but thanks for helping anyways.
yeah, I read it. Why do you think I expressed astonishment that you could not draw a simple triangle with angles labeled A,B,C ?
The angle don't have to be exact. It's just a diagram to work with. You know what a 45° angle looks like, I hope. Both angles A and B are fairly close to that.
To draw the diagram, start by drawing a triangle ABC. Label the angles <BAC as 46° and <ABC as 54°. Then, draw a perpendicular line from point C to meet AB at point D. Label the length of this altitude as 5.3cm.
Make sure to draw all the necessary markings:
- Label point A, B, C, and D.
- Draw a straight line connecting points A and B (side AB).
- Draw a straight line connecting points A and C (side AC).
- Draw a perpendicular line from point C to side AB and label the point of intersection as D.
- Indicate the length of the altitude by marking a line segment from point C to point D with a label of 5.3cm.
Remember to use a ruler and protractor to ensure accurate angles and measurements in the diagram.
What, you can't draw a triangle ABC and an altitude CD?
You are doomed...
5.3/AD = tan46°
AC^2 = AD^2 + 5.3^2