what is the solution of n^2-49=0
-7
7
±7
no solution
The answers for if you have 7 questions are:
c
d
b
b
c
b
a
NoU is 100% right!
n^2-49=0;
expand to (n-7)(n+7)=0;
thus, n-7=0 or n+7=0; n=7 and n=-7
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n^2-49=0;
n^2=49
n=± sqrt(49)
To find the solution of the equation n^2 - 49 = 0, we can use the square root property.
First, we want to isolate the variable n. Adding 49 to both sides of the equation, we get n^2 = 49.
Next, we take the square root of both sides. Remember that when taking the square root of a number, we consider both the positive and negative square roots.
Taking the square root of n^2 gives us two possibilities:
n = ±√49
Simplifying, we have two solutions:
n = 7 or n = -7
Therefore, the solutions to the equation n^2 - 49 = 0 are n = 7 and n = -7.
Add 49 to both sides.
What does n equal?