Algebra

Find two consecutive numbers if the square root of the smaller number is 3 less than the bigger number.

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asked by Sam
  1. 3 + sqrt x = x+1
    sqrt x = x - 2
    x = x^2 - 4 x + 4
    x^2 - 5 x + 4 = 0
    (x-4)(x-1) = 0
    x = 1 or 4
    check
    if x = 4
    2 = 5 - 3 yes so x = 4 and x+1 = 5
    if x = 1, no way

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    posted by Damon

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