# Algebra

Find two consecutive numbers if the square root of the smaller number is 3 less than the bigger number.

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1. 3 + sqrt x = x+1
sqrt x = x - 2
x = x^2 - 4 x + 4
x^2 - 5 x + 4 = 0
(x-4)(x-1) = 0
x = 1 or 4
check
if x = 4
2 = 5 - 3 yes so x = 4 and x+1 = 5
if x = 1, no way

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posted by Damon

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