Jarett was selling tickets to ride the Ferris wheel at a local carnival. The tickets cost $2.00 for adults , and $1.50 for children .How many of each kind of tickets did he sell if he sold a total of $300 tickets for$525
a+c = 300
2.00a + 1.50c = 525
now just solve for a,c
To solve this problem, we can set up a system of equations based on the given information.
Let's define variables:
A = number of adult tickets sold
C = number of children's tickets sold
Based on the given information, we have two equations:
1. A + C = 300 (equation #1), as the total number of tickets sold is 300.
2. 2A + 1.5C = 525 (equation #2), as the total revenue from the tickets is $525.
To solve this system of equations, we can use the method of substitution or elimination.
Let's use substitution:
From equation #1, we have A = 300 - C. Now, we substitute A in equation #2:
2(300 - C) + 1.5C = 525
Simplifying the equation, we get:
600 - 2C + 1.5C = 525
Combine like terms:
-0.5C = -75
Divide both sides by -0.5:
C = 150
Now that we know C is 150, we can substitute this value into equation #1 to find A:
A + 150 = 300
A = 300 - 150
A = 150
Therefore, Jarett sold 150 adult tickets and 150 children's tickets.