# Algebra

Which of the following functions is equivalent to the function below? Select two that apply.

f(x)=3 ^2x+1

1) g(x)=27^x
2) g(x)=9^x +1
3) g(x)=3^2x +3
4) g(x)=3⋅9^x
5) g(x)=2⋅3^x +1
6) g(x)=(1/3)^−(2x+1)

I selected answers 2 and 4. Are these correct?

I selected 4 because that one actually equal to the equation above and 2 because of it semi-equal it. My calculator(and the online ones I've went to) sucks, so I was hoping if anyone who's actually good at math, unlike myself, could tell me if these are correct or not.

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asked by Jean
1. the way you typed it ...
f(x)=3 ^2x+1
= 9x + 1, which does not match anything

unless you meant: f(x) = 3^(2x) + 1
which would be f(x) = (3^2)^x + 1
=9^x + 1 , which I do see

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posted by Reiny
2. I didn't type anything I copied and pasted it... And no on the test it says
3 ^2x+1 with the 2x+1 being an exponent. That's why I said I think number 4 is correct because when you put it into a calculator the answer is the one above.

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posted by Jean
3. Well then, copy and paste, without regards to whether it makes or not, and then
you expect us to try and interpret it?
So know you say : 3^(2x+1) , which gives it a totally different meaning.

3^(2x+1) = 3^(2x)*3^1
= 3*(3^2)^x
= 3*9^x

And I do see that as well.
Can't you see how your original statement is really ambiguous ?

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posted by Reiny
4. I can see how you didn't understand it, apologies for the misunderstanding. Again I am bad at math/algebra. Do you know any of the other answer(s) that are correct because it says I need "two" and I cannot figure the other one out?

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posted by Jean

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