A ball is thrown with an initial velocity of v feet per second, at an angle of θ with the horizontal (see figure in the link below). Find the vertical and horizontal components of the velocity. (Let v = 70 and θ = 40°. Round your answers to two decimal places.)
www.webassign.net/larprecalcrmrp6/6-3-097-alt.gif
vertical component (in ft/sec):
horizontal component (in ft/sec):
You might want to look at Khan Academy video of your problem
www.khanacademy.org/science/ap-physics-1/ap-two-dimensional-motion/projectiles-launched-at-an-angle-ap/v/optimal-angle-for-a-projectile-part-1
To find the vertical and horizontal components of the velocity, we can use the following formulas:
Vertical component of velocity (v_y) = v * sin(θ)
Horizontal component of velocity (v_x) = v * cos(θ)
Given that v = 70 ft/sec and θ = 40°, we can substitute these values into the formulas to calculate the components:
Vertical component:
v_y = 70 * sin(40°) ≈ 45.06 ft/sec (rounded to two decimal places)
Horizontal component:
v_x = 70 * cos(40°) ≈ 53.53 ft/sec (rounded to two decimal places)
Therefore, the vertical component of the velocity is approximately 45.06 ft/sec, and the horizontal component is approximately 53.53 ft/sec.