# math

smallest degree that satisfies 2cos^2x-3cosx=2

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1. 2cos^2x-3cosx=2
2cos^2x - 3cosx - 2 = 0
(2cosx + 1)(cosx - 2) = 0
cosx = -1/2 or cosx = 2, the last part is not possible

cosx = -1/2, so the smallest angle is in quadrant II
x = 120° or 2π/3 rads , assuming you wanted the smallest positive angle

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posted by Reiny

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