What is the slope of the line that goes through (6, 5) and (3, 1)?\
A. 3/4
B.-2/3
C. 4/3
D.-4/3
m = tan θ = ( y2 - y1 ) / ( x2 - x1 )
In this case:
Coordinates of point 1 , x1 = 6 , y1 = 5
Coordinates of point 2 , x2 = 3 , y2 = 1
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Remark:
( 6 , 5 ) mean
x coordinate of point 1 , x1 = 6
y coordinate of point 1 , y1 = 5
( 3 , 1 ) mean
x coordinate of point 2 , x2 = 3
y coordinate of point 2 , y2 = 1
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m = ( y2 - y1 ) / ( x2 - x1 ) =
( 1 - 5 ) / ( 3 - 6) = ( - 4 ) / ( - 3 ) = 4 / 3
To find the slope of a line given two points, you can use the formula:
slope (m) = (y2 - y1) / (x2 - x1)
In this case, the first point is (6, 5) and the second point is (3, 1).
Plugging in the values, we get:
slope = (1 - 5) / (3 - 6)
Simplifying, we have:
slope = -4 / (-3)
And this can be further simplified to:
slope = 4/3
So, the slope of the line that goes through (6, 5) and (3, 1) is 4/3.
Therefore, the correct answer is C. 4/3.