find the slope of the line
(1,-2) (3,2)
A. -2
B.2
C.-1/2
D.1/2
m = tan θ = ( y2 - y1 ) / ( x2 - x1 )
In this case:
Coordinates of point 1 , x1 = 1 , y1 = - 2
Coordinates of point 2 , x2 = 3 , y1 = 2
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Remark:
( 1 , - 2 ) mean
x coordinate of point 1 , x1 = 1
y coordinate of point 1 , y1 = - 2
( 3 , 2 ) mean
x coordinate of point 2 , x2 = 3
y coordinate of point 2 , y2 = 2
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m = ( y2 - y1 ) / ( x2 - x1 ) =
[ 2 - ( - 2 ) ] / (3 - 1) = ( 2 + 2 ) / 2 = 4 / 2 = 2
Thanx so much! :D
To find the slope of a line, you can use the formula:
slope = (change in y) / (change in x)
Let's apply this formula to the given set of points (1,-2) and (3,2).
First, identify the coordinates for each point:
Point 1: (x1, y1) = (1, -2)
Point 2: (x2, y2) = (3, 2)
Next, calculate the change in y (denoted as Δy) and the change in x (denoted as Δx):
Δy = y2 - y1
Δx = x2 - x1
Using the values from the given points:
Δy = 2 - (-2) = 4
Δx = 3 - 1 = 2
Now substitute the values into the slope formula:
slope = Δy / Δx = 4 / 2
Simplifying the fraction:
slope = 2
Therefore, the slope of the line passing through the points (1,-2) and (3,2) is 2.
So, the correct answer is B. 2.