A Petrol Engine Raises 200litres Of Water In A Well From A Depth Of 7m In 6 Sec.What Is The Power Of The Engine?
p=w/t
W=Mgh
1litir=1kg
200L=200kg
W=200kg*9.81m/s^2*7m
W=13734j
P=13734/6
P=2289watt
i give the answer step by step
Given Here
1litre=1kg,M=200kg,H=7m,T=6sec,P=W/T=mgh/t=200*9.8*7/6=2286.66
a litre of water has a mass of one kg
power = work / time = m g h / t = 200 * 9.8 * 7 / 6 ... watts
Well, if we're talking about a petrol engine raising water from a well, I'm guessing it's a pretty ambitious engine! But let's crunch the numbers to figure out its power.
First, we need to find the work done by the engine. Work is equal to force multiplied by distance. In this case, the force is the weight of the water, which we can calculate using its mass and acceleration due to gravity.
So, the weight of the water is 200 liters, which is equivalent to 200 kilograms (since 1 liter of water weighs about 1 kilogram). The acceleration due to gravity is approximately 9.8 m/s².
Now, we can find the work done by multiplying the weight of the water by the distance it was raised: 200 kg * 9.8 m/s² * 7 m = 13,720 joules.
Finally, power is defined as work done per unit of time. Since the engine raised the water in 6 seconds, we can divide the work by the time: 13,720 joules / 6 seconds = 2,286.7 watts.
So, it seems our ambitious petrol engine has a power of approximately 2,286.7 watts. That's not too shabby! Just imagine all the water it can raise... and all the water balloon fights it can dominate!
To determine the power of the engine, we need to use the equation:
Power = Work / Time
Where:
- Power is measured in watts (W)
- Work is measured in joules (J)
- Time is measured in seconds (s)
First, let's calculate the work done by the engine. In this case, the work is equal to the force exerted to raise the water multiplied by the distance the water is lifted.
Work = Force × Distance
The force required to lift the water can be calculated using the density of water and the volume of water lifted.
Density of water = 1000 kg/m³ (approximately)
Volume of water lifted = 200 liters = 0.2 m³
Therefore, the mass of water lifted (m) = density × volume = 1000 kg/m³ × 0.2 m³ = 200 kg
Next, calculate the gravitational force exerted on the water:
Gravitational force (F) = mass × acceleration due to gravity
Acceleration due to gravity = 9.8 m/s²
F = 200 kg × 9.8 m/s² = 1960 N
Finally, calculate the work done:
Work = Force × Distance
Distance = 7 m
Work = 1960 N × 7 m = 13720 J
Now, we have the work done, which is 13720 joules. We also have the time, which is 6 seconds.
Using the equation for power, we can substitute the values:
Power = Work / Time
Power = 13720 J / 6 s
Power = 2286.67 watts
Therefore, the power of the engine is approximately 2286.67 watts.